问泽西测试框架中的UnrecognizedPropertyException
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Stack Overflow用户

提问于 2015-12-04 01:40:40

回答 1查看 1.2K关注 0票数 0

我对泽西测试框架很陌生。我正在尝试在我的项目中使用jersey测试框架来实现测试用例。我有一项休息服务，其网址是：

http://localhost:8080/EzSupportBackend/a/dealerservices/getdealerdetails/FAB/ACZOKuBmtvyni16eMJ3AoSVg_HxL3bh3Lz0WiWNJhXudh9M90LSc8bDHD-Y2JpcbISZcC_DM2PL4yqSsmXUKA65ZmvuoiQ_wotgU1OvA8GGw_yPMwVnXGg==

我尝试用如下代码使用泽西岛来测试这个服务：

public class DealerServicesTest extends JerseyTest{
@Override
protected AppDescriptor  configure() {
    return new WebAppDescriptor.Builder().build();
}

@Test
public void testGetDealerDetails() throws JSONException,URISyntaxException {
    WebResource webResource = client().resource("http://localhost:8080/");
    JSONObject json = webResource.path("EzSupportBackend/a/dealerservices/getdealerdetails/FAB/ACZOKuBmtvyni16eMJ3AoSVg_HxL3bh3Lz0WiWNJhXudh9M90LSc8bDHD-Y2JpcbISZcC_DM2PL4yqSsmXUKA65ZmvuoiQ_wotgU1OvA8GGw_yPMwVnXGg==").get(JSONObject.class);

    assertEquals("ONLINE", json.get("companyType"));
    assertEquals("FabFurnish", json.get("companyName"));        
    assertEquals("Gurgoan,Haryana, India", json.get("companyAddress"));
    assertEquals("04222456803", json.get("phoneNumber"));
    assertEquals("ACTIVE", json.get("status"));     
    assertEquals("customerservice@fabfurnish.com", json.get("emailId"));
}
}

当我通过邮递员(Chrome扩展)测试这项服务时，我得到了如下正确的回应：

{
  "companyType": "ONLINE",
  "companyName": "FabFurnish",
  "companyAddress": "Gurgoan,Haryana, India",
  "companyLocation": null,
  "longitude": "77.023419",
  "phoneNumber": "04222456803",
  "serviceRating": 0,
  "repairRating": 0,
  "warrantyRating": 0,
  "shopRating": 0,
  "status": "ACTIVE",
  "createdOn": 1446613095557,
  "updatedOn": 1446613095557,
  "companyId": "FAB",
  "lattitde": "28.47427",
  "emailId": "customerservice@fabfurnish.com",
  "createdby": null,
  "updatedby": null
}

但是，通过这个测试，我得到了以下例外：

com.sun.jersey.api.client.ClientHandlerException:     com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "companyType" (class org.json.JSONObject), not marked as ignorable (0 known properties: ])
 at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@45b4c3a9; line: 1, column: 17] (through reference chain: org.json.JSONObject["companyType"])
    at com.sun.jersey.api.client.ClientResponse.getEntity(ClientResponse.java:563)
    at com.sun.jersey.api.client.ClientResponse.getEntity(ClientResponse.java:506)
    at com.sun.jersey.api.client.WebResource.handle(WebResource.java:674)
    at com.sun.jersey.api.client.WebResource.get(WebResource.java:191)
    at com.vs.mhs.ezsupport.services.DealerServicesTest.testGetDealerDetails(DealerServicesTest.java:27)

谁能帮我找出原因？？

编辑:我的代码如下所示：

@PermitAll
@GET
@Path("/getdealerdetails/{companyId}/{token_id}")
public Response getDealerDetails(@PathParam("companyId") String companyId, @Context SecurityContext userContext, @Context HttpServletRequest request){
    boolean isUserAuthorised = isUserAuthenticated(userContext);
    DealerDetails dealer = null;
    DealerDetailsView getDealerView = null;
    if(isUserAuthorised){
        EntityManager em = (EntityManager) request.getAttribute(FilterConstants.ENTITYMANAGER);
        DealerDetailsBDL dealerbdl = new DealerDetailsBDL(em);
        dealer = dealerbdl.getDealerDetails(companyId);
        getDealerView = new DealerDetailsView(dealer);
    }
    return Response.ok(getDealerView).build();          
}

DealerDetailsView是一个具有私有变量的类，用于我在下面列出的属性以及getter和setter：

private String companyid;
private String companyType;
private String companyName;
private String companyAddress;
private String companyLocation;
private String lattitude;
private String longitude;
private String phoneNumber;
private String emailid;
private int serviceRating;
private int repairRating;
private int warrantyRating;
private int shopRating;
private String status;

jersey-test-framework

java

unit-testing

junit

回答 1

Stack Overflow用户

回答已采纳

发布于 2015-12-04 02:02:38

Jackson是JSON提供者，Jackson通常使用模型POJO，而JSONObject不是。杰克逊正在寻找companyType在JSONObject的一个属性，但它并没有。所以你才会有例外。如果您没有专门针对该JSON的POJO，那么只需将其作为字符串获取，并使用该字符串创建JSONObject

String jsonString = webResource...get(String.class);
JSONObject json = new JSONObject(jsonString);

更新

用于Jackson的POJO只是一个将JSON字段映射到类属性(遵循JavaBean命名约定)的类。例如，对于这两个JSON字段

"companyType": "ONLINE",
"companyName": "FabFurnish"

你可以有这样的课程

public class CompanyInfo {
    private String companyType;
    private String companyName;

    public CompanyInfo() {}

    public String getCompanyInfo() { return companyInfo; }
    public void setCompanyInfo(String info) { this.companyInfo = info; }
    
    public String getCompanyType() { return companyType; }
    public void setCompanyType(String type) { this.companyType = type; }
}