我希望从OpenApiSchema
6中的任何给定Json对象动态生成.Net。我在代码中没有clr类型可以自动生成Swashbuckle使用的Open,并且需要通过编程方式这样做,并且不需要使用单个对象生成器工具。此外,这些Json对象将由其他用户频繁地更改。我的目标是从给定的json有效负载动态创建OpenAPI规范。给出如下所示的随机Json,并使用C#生成类似于此方法的OpenApiSchema
,https://taerimhan.com/exploring-openapi-extensions-dynamic-schema/。我需要做的主要区别是将结果直接连接到OpenAPI,这样就可以动态地呈现schmeas和属性。看Json样本..。
{
"id": "123",
"unassumablepropertyname1": {
"id": "456",
"otherprop": null
},
"dynamicproperty": "456",
"somethinguseful": "ABC123"
}
理想的结果是动态生成这样的OpenAPI V3规范.
{
"openapi": "3.0.1",
"info": {
"title": "Sample API Capabilities",
"version": "v1"
},
"paths": {
"/api/DataRecord/UpsertDynamicObj12": {
"post": {
"tags": [
"Dynamic Objects"
],
"operationId": "UpsertDynamicExample",
"requestBody": {
"content": {
"application/json": {
"schema": {
"$ref": "#/components/schemas/DynamicObj12"
}
},
"text/json": {
"schema": {
"$ref": "#/components/schemas/DynamicObj12"
}
},
"application/*+json": {
"schema": {
"$ref": "#/components/schemas/DynamicObj12"
}
}
}
},
"responses": {
"200": {
"description": "Success"
}
}
}
}
},
"components": {
"schemas": {
"DynamicObj12": {
"required": [
"id"
],
"type": "object",
"properties": {
"id": {
"type": "string"
},
"dynamicproperty": {
"type": "string"
},
"somethinguseful": {
"type": "string"
},
"unassumablepropertyname1": {
"type": "array",
"items": {
"$ref": "#/components/schemas/UnassumablePropertyName1"
},
"nullable": true
}
},
"additionalProperties": false
},
"UnassumablePropertyName1": {
"required": [
"id"
],
"type": "object",
"properties": {
"id": {
"type": "string",
"format": "uuid"
},
"otherprop": {
"type": "string",
"format": "uuid"
}
},
"additionalProperties": false
}
}
}
}
我查看了下面的资源,这些资源非常接近,但是我正在寻找一个C#解决方案,这样我就可以对许多不同Json形状的对象使用Swashbuckle。
有什么想法吗?
发布于 2022-10-10 15:38:20
不幸的是,从我所探讨的情况来看,这是不可能的。在Swashbuckle中构建OpenAPI片段是可能的,但我不知道如何在您的情况下应用它。
https://stackoverflow.com/questions/73994401
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