问对ResultSelector进行语法调优以从Step函数状态机提取正确的输出
EN

Stack Overflow用户

提问于 2022-11-17 08:06:02

回答 1查看 21关注 0票数 1

我有一个状态机，它有一个映射状态，遍历一个由2个元素组成的数组，其输出如下：

[
  {
    "BillingDetails": {
      "BilledDurationInMilliseconds": 100,
      "BilledMemoryUsedInMB": 64
    },
    "ExecutionArn": "arn:aws:states:us-west-2:693935722839:express:restaurantdbread:53054495-6e74-47bb-b58e-ad1f40b8282e:255e2717-5126-422a-81e4-b13e505a2f16",
    "Input": "{\"restaurant_name\":\"outback\"}",
    "InputDetails": {
      "Included": true
    },
    "Name": "53054495-6e74-47bb-b58e-ad1f40b8282e",
    "Output": "\"27\"",
    "OutputDetails": {
      "Included": true
    },
    "StartDate": "2022-11-17T08:47:30.364Z",
    "StateMachineArn": "arn:aws:states:us-west-2:693935722839:stateMachine:restaurantdbread",
    "Status": "SUCCEEDED",
    "StopDate": "2022-11-17T08:47:30.435Z"
  },
  {
    "BillingDetails": {
      "BilledDurationInMilliseconds": 100,
      "BilledMemoryUsedInMB": 64
    },
    "ExecutionArn": "arn:aws:states:us-west-2:693935722839:express:restaurantdbread:7d1597ea-973a-41ac-bf16-f506dd745566:f72ecfc1-93fc-47aa-a494-e925f9c95214",
    "Input": "{\"restaurant_name\":\"ihop\"}",
    "InputDetails": {
      "Included": true
    },
    "Name": "7d1597ea-973a-41ac-bf16-f506dd745566",
    "Output": "\"0\"",
    "OutputDetails": {
      "Included": true
    },
    "StartDate": "2022-11-17T08:47:30.366Z",
    "StateMachineArn": "arn:aws:states:us-west-2:693935722839:stateMachine:restaurantdbread",
    "Status": "SUCCEEDED",
    "StopDate": "2022-11-17T08:47:30.437Z"
  }
]

我需要编写一个如下所示的输出：

[{"name": "outback", "value": 27}, {"name": "chipotle", "value": 0}]

将以下ResultSelector添加到我的状态机

            "ResultSelector": {
                "name.$": "States.StringToJson($.Input)", 
                "value.$": "States.StringToJson($.Output)"
            },

现在我得到了接近我所需要的东西：

[
  {
    "name": {
      "restaurant_name": "outback"
    },
    "value": "27"
  },
  {
    "name": {
      "restaurant_name": "ihop"
    },
    "value": "0"
  }
]

我正在努力调整输出，以便"restaurant_name"：get被丢弃以实现所需的格式。

我试图调整ResultSelector以使用：

            "ResultSelector": {
                "name.$": "States.StringToJson($.Input.restaurant_name)", 
                "value.$": "States.StringToJson($.Output)"
            },

但是工作流吐出了这个错误：

The function 'States.StringToJson($.Input.restaurant_name)' had the following error: The JsonPath argument for the field '$.Input.restaurant_name' could not be found in the input '{"BillingDetails":{"BilledDurationInMilliseconds":100,"BilledMemoryUsedInMB":64},"ExecutionArn":"arn:aws:states:us-west-2:693935722839:express:restaurantdbread:b8e9de51-1806-47ab-b4e6-1c60d6cd9fc1:9ce2cb9d-0b57-4066-b7de-a41668d6113f","Input":"{\"restaurant_name\":\"ihop\"}","InputDetails":{"Included":true},"Name":"b8e9de51-1806-47ab-b4e6-1c60d6cd9fc1","Output":"\"0\"","OutputDetails":{"Included":true},"StartDate":"2022-11-17T08:58:44.627Z","StateMachineArn":"arn:aws:states:us-west-2:693935722839:stateMachine:restaurantdbread","Status":"SUCCEEDED","StopDate":"2022-11-17T08:58:44.686Z"}'

对于只提取餐厅名称的语法有什么建议吗？

amazon-web-services

aws-step-functions

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回答 1

Stack Overflow用户

发布于 2022-11-18 05:13:09

我能够通过添加一个新的map状态来解决(或解决)我的问题，该状态分解输入中的数组并将Parameters应用于Pass任务。这是附加状态的样子：

    "Map formatting": {
      "Type": "Map",
      "End": true,
      "Iterator": {
        "StartAt": "Pass",
        "States": {
          "Pass": {
            "Type": "Pass",
            "End": true,
            "Parameters": {
              "name.$": "$.name.restaurant_name",
              "value.$": "$.value"
            }
          }
        }
      }
    }