【C语言小游戏】——扫雷(超详细过程+完整代码)

#pragma once
#include<stdio.h>
#include<stdlib.h>
#include<time.h>

#define ROW 9
#define COL 9
#define ROWS ROW+2
#define COLS COL+2

#define EASY_COUNT 10

//棋盘初始化的函数
 void InitBoard(char arr[ROWS][COLS], int rows, int cols,int set);

 //打印棋盘
 void DisplayBoard(char arr[ROWS][COLS], int row, int col);

 //布置雷
 void SetMine(char arr[ROWS][COLS], int row, int col);

 //排查雷
  void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

#include "game.h"

void InitBoard(char arr[ROWS][COLS], int rows, int cols,int set)
{
	int i;
	int j;
	for (i = 0; i < rows; i++)
	{
		
	    for (j = 0; j < cols; j++)
		{
			arr[i][j] = set;
		}
	}
}

void DisplayBoard(char arr[ROWS][COLS], int row, int col)
{
	int i=0;
	int j=0;
	printf("------扫雷游戏------\n");
	for (i = 0; i <= col; i++)
	{
		printf("%d ", i);
	}
	printf("\n");
	for (i = 1; i <=row; i++)
	{
		printf("%d ", i);
		for (j = 1; j<=col; j++)
		{
			printf("%c ", arr[i][j]);
		}
		printf("\n");
	}
}

void SetMine(char arr[ROWS][COLS], int row, int col)
{
	int count = EASY_COUNT;
	while (count)
	{
		int x = rand() % row + 1;//保证坐标是1-9
		int y = rand() % col + 1;
		if (arr[x][y] == '0')
		{
			arr[x][y] = '1';
			count--;
		}
	}
}

int GetMineCount(char mine[ROWS][COLS], int x, int y)
{
	return mine[x - 1][y + 1] +
		mine[x - 1][y - 1] +             //'0'--48  '1'--49 '2'--50···
		mine[x][y - 1] +                 
		mine[x + 1][y - 1] +
		mine[x + 1][y] +
		mine[x + 1][y + 1] +
		mine[x][y + 1] +
		mine[x - 1][y + 1] -8 * '0';
}


void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
	int x=0;
	int y=0;
	int win = 0;
	while (win< row*col-EASY_COUNT)
	{
		printf("请输入要排查的坐标：");
		scanf("%d %d", &x, &y);
		//判断坐标有效性
		if (x>=1&&x<=row&&y<=col&&y>=1)
		{
				if (mine[x][y] == '1')
				{
					printf("很遗憾你被炸死了\n");
					DisplayBoard(mine, ROW, COL);
					break;
				}
				else
				{
					//该坐标不是雷，就得统计坐标周围有几个雷
					int count = GetMineCount(mine, x, y);//GetMineCount为排雷准备的
					show[x][y] = count + '0';
					//DisplayBoard(show, ROW, COL);
					win++;
					DisplayBoard(show, ROW, COL);
				}
		}
		else
		{
			printf("坐标非法，请重新输入\n");
		}
	   
	}
	if (win == row * col - EASY_COUNT)
	{
		printf("恭喜你排雷成功\n");
		DisplayBoard(mine, ROW, COL);;
	}
}

#include "game.h"
//打印菜单(无参数，无返回值）
void menu()
{
	printf("*******************\n");
	printf("****  1. PLAY  ****\n");
	printf("****0.退出游戏 ****\n");
	printf("*******************\n");
}

//完成扫雷游戏
void game()
{
    //mine数组存放布置好的雷的信息
	char mine[ROWS][COLS] = { 0 };//数组全部初始化为'0'
	//show数组存放排查好的雷的信息
	char show[ROWS][COLS] = { 0 };//数组全部初始化为'*'
	//初始化棋盘
	InitBoard(mine, ROWS, COLS,'0');
	InitBoard(show, ROWS, COLS, '*');


//打印棋盘
	DisplayBoard(mine, ROW, COL);
	//DisplayBoard(show, ROW, COL);

//布置雷，即在9*9的棋盘上随机布置10个雷
	SetMine(mine, ROW, COL);
	DisplayBoard(mine, ROW, COL);

//排查雷过程，在mine中排查，放到show中
	FindMine(mine, show, ROW, COL);

}

void  test()
{
    int input = 0;
	srand((unsigned int)time(NULL));
	do
	{
		menu();
		printf("请选择：");//1 0 x
			scanf("%d", &input);
			switch (input)
			{
			case 1:
				game();
				break;
			case 0:
				printf("游戏结束\n");
				break;
			default:
				printf("选择错误，请重新选择\n");
				break;

			}
	} while (input);//如果选0，则为假，退出循环
}

int main()
{
	test();
	return 0;
}