C:将getline()创建的字符串存储在链表中？

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

// 定义链表节点结构
typedef struct Node {
    char* str;
    struct Node* next;
} Node;

// 创建链表节点
Node* createNode(char* str) {
    Node* newNode = (Node*)malloc(sizeof(Node));
    newNode->str = (char*)malloc(strlen(str) + 1);
    strcpy(newNode->str, str);
    newNode->next = NULL;
    return newNode;
}

// 将字符串存储在链表中
void storeStringInLinkedList(Node** head, char* str) {
    Node* newNode = createNode(str);
    if (*head == NULL) {
        *head = newNode;
    } else {
        Node* current = *head;
        while (current->next != NULL) {
            current = current->next;
        }
        current->next = newNode;
    }
}

// 打印链表中的字符串
void printLinkedList(Node* head) {
    Node* current = head;
    while (current != NULL) {
        printf("%s\n", current->str);
        current = current->next;
    }
}

// 释放链表内存
void freeLinkedList(Node* head) {
    Node* current = head;
    while (current != NULL) {
        Node* temp = current;
        current = current->next;
        free(temp->str);
        free(temp);
    }
}

int main() {
    Node* head = NULL;
    char input[100];

    // 读取字符串并存储在链表中
    while (fgets(input, sizeof(input), stdin) != NULL) {
        input[strcspn(input, "\n")] = '\0';  // 去除换行符
        storeStringInLinkedList(&head, input);
    }

    // 打印链表中的字符串
    printLinkedList(head);

    // 释放链表内存
    freeLinkedList(head);

    return 0;
}