将R- list转换为特定格式的数据帧？

# 示例列表
my_list <- list(
  name = c("Alice", "Bob", "Charlie"),
  age = c(25, 30, 35),
  city = c("New York", "Los Angeles", "Chicago")
)

# 转换为数据帧
df <- as.data.frame(my_list)
print(df)

library(tidyverse)

# 示例嵌套列表
nested_list <- list(
  list(name = "Alice", age = 25, city = "New York"),
  list(name = "Bob", age = 30, city = "Los Angeles"),
  list(name = "Charlie", age = 35, city = "Chicago")
)

# 转换为数据帧
df_nested <- bind_rows(nested_list)
print(df_nested)

# 示例不规则列表
irregular_list <- list(
  name = c("Alice", "Bob"),
  age = c(25, 30, 35),
  city = c("New York", "Los Angeles")
)

# 使用bind_rows处理不规则列表
df_irregular <- bind_rows(irregular_list, .id = "source")
print(df_irregular)