如何确保java中的矩形是有效的矩形？

import java.awt.Rectangle;

public class RectangleValidation {
    public static boolean isValidRectangle(Rectangle rectangle) {
        int width = rectangle.width;
        int height = rectangle.height;
        double diagonalLength = rectangle.getDiagonalLength();

        // 确保宽度和高度大于零
        if (width <= 0 || height <= 0) {
            return false;
        }

        // 确保边界是平行于坐标轴的
        if (rectangle.getWidth() != width || rectangle.getHeight() != height) {
            return false;
        }

        // 确保四个角是直角
        double slope1 = (double) height / width;
        double slope2 = (double) width / height;
        if (slope1 * slope2 != -1) {
            return false;
        }

        // 确保对角线长度满足勾股定理
        double side1Length = Math.sqrt(width * width + height * height);
        double side2Length = Math.sqrt(width * width + height * height);
        if (diagonalLength * diagonalLength != side1Length * side1Length + side2Length * side2Length) {
            return false;
        }

        return true;
    }

    public static void main(String[] args) {
        Rectangle rectangle = new Rectangle(0, 0, 5, 10);
        System.out.println(isValidRectangle(rectangle));  // 输出false

        rectangle = new Rectangle(0, 0, 5, 5);
        System.out.println(isValidRectangle(rectangle));  // 输出true
    }
}