如何将数组中的浮点值转换为对应的时序时间进行比较

import time

def convert_to_timestamp(value, unit):
    if unit == 's':
        return int(value * 1000)  # 转换为毫秒级时间戳
    elif unit == 'ms':
        return int(value)
    elif unit == 'us':
        return int(value / 1000)
    else:
        raise ValueError("Unsupported time unit")

def compare_timestamps(array, unit):
    timestamps = [convert_to_timestamp(value, unit) for value in array]
    min_timestamp = min(timestamps)
    max_timestamp = max(timestamps)
    return min_timestamp, max_timestamp

# 示例数组
array = [1.23, 4.56, 7.89, 2.34, 5.67]

# 比较毫秒级时间戳
min_timestamp, max_timestamp = compare_timestamps(array, 'ms')
print("最小时间戳：", min_timestamp)
print("最大时间戳：", max_timestamp)