如何在不影响操作数的情况下重载按位运算符？

class Number:
    def __init__(self, value):
        self.value = value

    def __and__(self, other):
        return Number(self.value & other.value)

    def __or__(self, other):
        return Number(self.value | other.value)

    def __xor__(self, other):
        return Number(self.value ^ other.value)

    def __invert__(self):
        return Number(~self.value)

    def __lshift__(self, other):
        return Number(self.value << other.value)

    def __rshift__(self, other):
        return Number(self.value >> other.value)

    def __repr__(self):
        return str(self.value)

# 示例用法
num1 = Number(5)
num2 = Number(3)

result = num1 & num2
print(result)  # 输出: 1

result = num1 | num2
print(result)  # 输出: 7

result = ~num1
print(result)  # 输出: -6

result = num1 << num2
print(result)  # 输出: 40

result = num1 >> num2
print(result)  # 输出: 0