如何以快速安全的方式将十六进制字符串转换为无符号64位(uint64_t)整数？

#include <iostream>
#include <string>

uint64_t hexStringToUint64(const std::string& hexString) {
    // 验证输入合法性
    if (hexString.empty() || hexString.size() > 16) {
        throw std::invalid_argument("Invalid hex string");
    }

    // 将十六进制字符串转换为无符号长长整型
    uint64_t decimalValue = std::stoull(hexString, nullptr, 16);

    return decimalValue;
}

int main() {
    std::string hexString = "ABCDEF1234567890";
    try {
        uint64_t result = hexStringToUint64(hexString);
        std::cout << "转换结果: " << result << std::endl;
    } catch (const std::exception& e) {
        std::cout << "转换失败: " << e.what() << std::endl;
    }

    return 0;
}