如何以不同的语言搜索(.filter)？

numbers = [1, 2, 3, 4, 5, 6]
even_numbers = list(filter(lambda x: x % 2 == 0, numbers))
print(even_numbers)

[2, 4, 6]

const numbers = [1, 2, 3, 4, 5, 6];
const evenNumbers = numbers.filter(x => x % 2 === 0);
console.log(evenNumbers);

[2, 4, 6]

import java.util.Arrays;
import java.util.List;

public class Main {
    public static void main(String[] args) {
        List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6);
        List<Integer> evenNumbers = numbers.stream()
                                           .filter(x -> x % 2 == 0)
                                           .collect(Collectors.toList());
        System.out.println(evenNumbers);
    }
}

[2, 4, 6]

using System;
using System.Collections.Generic;
using System.Linq;

public class Program
{
    public static void Main()
    {
        List<int> numbers = new List<int> { 1, 2, 3, 4, 5, 6 };
        List<int> evenNumbers = numbers.Where(x => x % 2 == 0).ToList();
        Console.WriteLine(string.Join(", ", evenNumbers));
    }
}

2, 4, 6