处理并集与交集Typescript的问题

const set1 = [1, 2, 3];
const set2 = [3, 4, 5];

// 使用concat()方法
const unionSet = set1.concat(set2);
console.log(unionSet); // [1, 2, 3, 3, 4, 5]

// 使用扩展运算符
const unionSet = [...set1, ...set2];
console.log(unionSet); // [1, 2, 3, 3, 4, 5]

const set1 = [1, 2, 3];
const set2 = [3, 4, 5];

const intersectionSet = set1.filter((value) => set2.includes(value));
console.log(intersectionSet); // [3]