在java中对具有相同哈希码的对象进行排序

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;

class Person {
    private String name;
    private int age;

    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }

    public int getAge() {
        return age;
    }

    @Override
    public int hashCode() {
        return name.hashCode(); // 假设基于名字的哈希码可能相同
    }

    @Override
    public String toString() {
        return name + ":" + age;
    }
}

public class Main {
    public static void main(String[] args) {
        List<Person> people = new ArrayList<>();
        people.add(new Person("Alice", 30));
        people.add(new Person("Bob", 25));
        people.add(new Person("Charlie", 30)); // 哈希码可能与Alice相同

        // 使用Comparator根据年龄排序
        Collections.sort(people, new Comparator<Person>() {
            @Override
            public int compare(Person p1, Person p2) {
                return Integer.compare(p1.getAge(), p2.getAge());
            }
        });

        // 打印排序后的列表
        for (Person person : people) {
            System.out.println(person);
        }
    }
}