在Java中使用Xml的简单方法

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import java.io.File;

public class XmlParser {
    public static void main(String[] args) {
        try {
            File inputFile = new File("example.xml");
            DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
            DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
            Document doc = dBuilder.parse(inputFile);
            doc.getDocumentElement().normalize();

            NodeList nodeList = doc.getElementsByTagName("employee");
            for (int i = 0; i< nodeList.getLength(); i++) {
                Node node = nodeList.item(i);
                if (node.getNodeType() == Node.ELEMENT_NODE) {
                    Element element = (Element) node;
                    System.out.println("Employee ID: " + element.getAttribute("id"));
                    System.out.println("Employee Name: " + element.getElementsByTagName("name").item(0).getTextContent());
                    System.out.println("Employee Age: " + element.getElementsByTagName("age").item(0).getTextContent());
                }
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}