strRetain; @property (nonatomic, strong) NSString *strStrong; @property (nonatomic, copy) NSString *strCopy...NSString *name = @"原XM"; 3 [per setStrRetain:name]; 4 [per setStrStrong:name]; 5 per.strCopy...: %@", per.strCopy); 16 NSLog(@"per.strMutableRetain: %@", per.strMutableRetain); 17 NSLog(@"...: %@", per.strCopy); 27 NSLog(@"per.strMutableRetain: %@", per.strMutableRetain); 28 NSLog(@"...: %@", per.strMutableCopy); 打印日志: ------ 改变之前打印 ------ per.strRetain: 原XM, per.strStrong: 原XM per.strCopy
int pre(char *string, char *strCopy) { strCopy[0] = ‘$’; int j = 1; for (int i = 0; i < strlen(string...); i++) { strCopy[j++] = ‘#’; strCopy[j++] = string[i]; } strCopy[j] = ‘#’; return j + 1;//表示strCopy...; else start = i – p[i] – 1; } } } int main(void) { char string[] = “acab”;//”abcdeedcbdac”; char strCopy...[MAXLEN]; int len = pre(string, strCopy); printf(“原串:%s –>”, string); //输出strCopy for (int i = 0; i <...len; i++){ printf(“%c”, strCopy[i]); } printf(“\n”); manacher(strCopy,len); printf(“\t%s的最长回文子串:\n
void splitWithStrtok(const char* str, const char* delim, vector& ret) { char* strcopy = new...char[strlen(str) + 1]; strcpy(strcopy, str); char *word = strtok(strcopy, delim); ret.push_back...(word); while (word = strtok(nullptr, delim)) ret.push_back(word); delete[] strcopy;
正文 void strCopy(char *dest, const char *str, int len) { if (str == nullptr) { return;...ret = (char *) malloc(sizeof(char) * (len + 1)); memset(ret, 0, sizeof(char) * (len + 1)); strCopy
= '/0'; i++) data[i] = cstr[i]; length = i; } // 将串s复制给当前串SqSting public void StrCopy(SqString...str.data[i] = data[i]; for (i = 0; i < s.length; i++) str.data[length + i] = s.data[i]; this.StrCopy...s.length++] = data[k]; for (k = i + j - 1; k < length; k++) s.data[s.length++] = data[k]; this.StrCopy...StrAssign(cstr2); System.out.print("s2:"); s2.DispStr(); SqString s3 = new SqString(); s3.StrCopy...strCopy(T,S):串S存在,由串S复制得串T ClearString(S):串S存在,将串清空 StringEmpty(S):若串S为空,返回true,否则false StrLength
AREA StrCopy, CODE, READONLY ENTRY CODE32 start LDR R1, =srcstr...; 调用子程序strcopy,完成字符串拷贝 stop MOV R0, #0x18 ; 程序结束返回编译器调试环境 LDR R1..., =0x20026 SWI 0x123456 strcopy LDRB R2, [R1], #1 ; 将R1指向的单元内容加载到...; 将R2中的数存储到R0指向的单元中 CMP R2, #0 ; 检查R0的值是否等于0 BNE strcopy...; 如果不等于0,那么转到strcopy处执行 MOV PC, LR ; 子程序返回
main.c extern int add(int a,int b); printf("%d \n",add(2,3)); a->r0,b->r1 返回值通过r0返回计算结果给c代码 例2,用汇编实现一个strcopy...函数 ;.asm .global strcopy strcopy: ;R0指向目的字符串 ;R1指向源字符串 LDRB R2, [R1], #1 ;加载字字符并更新源字符串指针地址...STRB R2, [R0], #1 ;存储字符并更新目的字符串指针地址 CMP R2, #0 ;判断是否为字符串结尾 BNE strcopy ;如果不是,程序跳转到strcopy继续循环...MOV pc, lr ;程序返回 //.c #include extern void strcopy(char* des, const char* src); int...main(){ const char* srcstr = "yikoulinux"; char desstr[]="test"; strcopy(desstr, srcstr); return
操作 诠释 StrAssign(T, *chars) 生成一个其值等于字符串常量chars的串T StrCopy(T,S) 串S存在,由串S复制得到T ClearString(S) 若S存在,将串清空...//// 2 3 function MyString(strArray) { 4 //均需依赖于数组的操作 5 this.strArray = strArray; 6 this.strCopy...= ['t', 't']; 106 107 var str = new MyString(strArray); 108 console.log(str); 109 var newStr = str.strCopy
{p=(LinkedList)malloc( sizeof(node)); strcopy(p->data,a);p->freg=1;p->next=null;pre->next=p; } ∥将新结点插入到链表最后...{p=(LinkedList)malloc( sizeof(node)); strcopy(p->data,a);p->freg=1;p->next=null;pre->next=p; }∥ if 新结点插入
pointer: %p content: %@", strA, strA); NSString *strACopy = [strA copy]; NSLog(@"strCopy...pointer: %p content: %@", strBMCopy, strBMCopy); //输出 strA pointer: 0x100003180 content: origin strCopy
StrEmpty(SString S){ if(S.length==0) return true; return false; } 复制:把串S复制得到串T bool StrCopy...,'d','e','f','g'}; for(int i=1;i<=7;i++){ Insert(S1,i,a[i-1]); } Print(S1); StrCopy
=Src ; 先将原字符串地址加载到R0 LDR R1, =Dst ; 将目的字符串地址加载到R1 MOV R3,#0 ; 定义R3中的内容为0 strcopy...endcopy STRB R2,[R1],#1 ; 先将R2中的字节数据写入R1中,并把地址R1+1的值存入R1 ADD R3,R3,#1 ; R3自加一,用于记录字符个数 B strcopy
< MAXSIZE; i++) Dest[i] = ptr[i]; Dest[i] = '\0'; return true; } /* 拷贝一个字符串 */ bool StrCopy...void) { String Str1; StrAssign(Str1, "ILOVEYOU"); StrPrint(Str1); String Str2; StrCopy
strcopy(user[av].data,s); p=1; ∥p为工作指针(下标) if(strcmp(user[p].data,s)<0)∥沿右链查找 {while (p!
StringNode * next; }StringNode, *String; 存储密度提高 5、基本操作的实现 StrAssign(&T, chars): 赋值操作,把串T赋值为chars; StrCopy
oChildThread[i].nIndex := i; strcopy(@oChildThread[i].szName,PChar('Child' + IntToStr(i)));
随后调用了strcopy函数,将传递进来的参数直接copy到了buf中,并没有检测传入的数据长度,看来溢出的入口就是这里了。
2.8.2 复制的实现 StrCopy(&T,S)——将串S的内容拷贝到串T中。...>length = chars->length;//修改当前串长 T->maxsize = chars->maxsize;//修改最大串长 return true; } //串的复制 void StrCopy...HString* T); //求串长 int StrLength(char* S); //串的赋值 bool StrAssign(HString* T, HString* chars); //串的复制 void StrCopy...} else { printf("串K初始化失败\n"); return; } } //串复制 if (1) { printf("串复制操作测试:>\n"); StrCopy...复制失败\n"); return; } else { printf("串S复制成功\n"); StrPrint(S, 'S');//打印串S的内容、当前串长与最大串长 } StrCopy
• 不要使用C风格字符串(char*'),也不要使用strelen()和strcopy()等函数。std::string更安全,还提供了很多有用的方法,如获取长度、进行复制和附加的方法。
); 18 NSString* str = @"fkit"; 19 // 复制str(不可变字符串)的可变副本 20 NSMutableString* strCopy...= [str mutableCopy]; //① 21 // 向可变字符串后面追加字符串 22 [strCopy appendString:@".org"]; 23...NSLog(@"%@" , strCopy); 24 // 调用book(可变字符串)的copy方法,程序返回一个不可修改的副本 25 NSMutableString*
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