我正在尝试使用以下查询从mysql数据库中获取用户详细信息 $query = "SELECT CONCAT(usrFirstnameusrNickname AS Nickname,";
$query.= "usrEmail As EmailAddress,usrGender AS Gender,DATE_FORMAT(usrDOB,'%d%m%y') As DOB,usrBelt AS B
我需要您的帮助来查看我的sql和表中有什么问题。$result = mysql_query("SELECT DATE_FORMAT(thedate, '%Y %M %D') AS d, count(semail) AS av FROM `ecard2008` WHERE `sflag`='1' AND `thedate`>='2000-12-12' GROUP BY `thedate`")or die(mysql_error());