sqltabla="select * from precotizacion p, producto pro where p.idproducto=pro.id"; $dato=mysql_fetch_array($resutadotabla);
while ($dato=mysql_fetch_array
我试图在MySQL中执行PL/SQL语句。但是,当我试图创建一个表时,它会显示一个语法错误。ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQLEXIT WHEN practical2_sequence.CURRVAL >= 100; END; SELECT * FROM supplier;
帮助我,因为我在MySQL