下面的PHP代码报告一个错误代码:$q = mysql_query("select * from messages where seen=0 and to$q){die("critical failure: ".mysql_error());}critical failure: You have an error in your SQLsyntax; check the manual that corresponds to your
我得到的错误是,您的SQL语法中有一个错误;请查看与您的MySQL服务器版本对应的手册,以获得正确的语法,以便在第1行使用接近'keys %dogs% ORDER BY rating DESC‘的键$query = mysql_query("SELECT * FROM listings WHERE keys LIKE %$q% ORDER BY rating DESC") or die(mysql_error
我在让SQL "use“命令在MySQL 5.7中工作时遇到问题。
我有一个带有“字符”表的数据库'mydb‘。(目前,桌子是空的,但我认为这在这里不重要)。You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version