name="+name.toLowerCase().replace(" ","_");$name = mysql_real_escape_string($_GET['name']);$query = "select * from authinfo where name LIKE '$name'";
mysql_quer
我有$countB= mysql_query ("select count (PID) from B where DID=('$_POST[DID])");while($row = mysql_fetch_array我如何在我的计数查询中执行where,以获得用户在输入框中输入的值?我做得完全错了吗?
谢谢!
FYI using PHP Version 5.5.12,Apache Version Apache/2.4.9 (Win64) PHP/5.5.12
严重程度: 8192文件名:model/models_model.线路号码: 21文件: C:\wamp\www\Codeigniter\application\models\common_model.php行: 21功能: