我正在阅读Linux2.6.11 sys_sigsuspend的实现如下
34 /*
35 * Atomically swap in the new signal mask, and wait for a signal.
36 */
37 asmlinkage int
38 sys_sigsuspend(int history0, int history1, old_sigset_t mask)
39 {
40 struct pt_regs * regs = (struct pt_regs *) &history0;
41 sigse
让我们用一个小程序来捕获(并忽略) SIGTERM信号: # nosigterm.py:
import signal
import time
def ignore(signum, frame):
print("Ignoring signal {}".format(signum))
if __name__ == '__main__':
signal.signal(signal.SIGINT, ignore)
signal.signal(signal.SIGTERM, ignore)
while True:
time.slee
我是否可以区分信号,直接传递给进程和通过调试器传递。
案例1:
$ ./process1
process1 (not ptraced)
//set up handler
alarm(5);
....
//signal is handled and I can parse handler parameters
案例2:
$ debugger1 ./process1
process1 (is ptraced by debugger1)
//set up handler
alarm(5);
...
//signal is catched by debugger1. It re
以这个简单的例子为例:
public class Main
{
public static void main(String[] args) throws Exception
{
Runtime.getRuntime().exec("sleep 1000");
// This is just so that the JVM does not exit
Thread.sleep(1000 * 1000);
}
}
我正在使用openjdk6在Linux上运行这个程序。如果我试图向“睡眠”进程发送一个SIGQ
通常Linux中的崩溃报告可能如下所示:
[jack-VirtualBox:14564] *** Process received signal ***
[jack-VirtualBox:14564] Signal: Segmentation fault (11)
[jack-VirtualBox:14564] Signal code: (-6)
[jack-VirtualBox:14564] Failing at address: 0x3e8000038e4
[jack-VirtualBox:14564] [ 0] /lib/x86_64-linux-gnu/libpthread.so.0
我想知道UNIX信号的安全性。
SIGKILL会扼杀这个过程。那么,当非根用户的进程向根用户的进程发送信号时会发生什么呢?这个过程还在执行信号处理程序吗?
我遵循公认的答案(gollum's),输入man capabilites,我发现了许多关于Linux内核的内容。来自man capabilities:
NAME
capabilities - overview of Linux capabilities
DESCRIPTION
For the purpose of performing permission checks, traditional UNIX
im