linux比较两个数字大小

echo "a=10; b=20; if(a>b) print \"a is greater\" else print \"b is greater\"" | bc

echo "10 20" | awk '{if ($1 > $2) print "First number is greater"; else print "Second number is greater"}'

#!/bin/bash

num1=10
num2=20

if [ $num1 -gt $num2 ]; then
  echo "$num1 is greater than $num2"
elif [ $num1 -lt $num2 ]; then
  echo "$num1 is less than $num2"
else
  echo "$num1 is equal to $num2"
fi

#include <stdio.h>

int main() {
    int num1 = 10, num2 = 20;

    if (num1 > num2) {
        printf("%d is greater than %d\n", num1, num2);
    } else if (num1 < num2) {
        printf("%d is less than %d\n", num1, num2);
    } else {
        printf("%d is equal to %d\n", num1, num2);
    }

    return 0;
}

import math

a = 0.1 + 0.2
b = 0.3

if math.isclose(a, b):
    print("a and b are close enough")
else:
    print("a and b are not close enough")