我想在我的RankingView中创建一个列表,以显示我的球员的排名。排序的类型可以在选择者中选择。玩家可以通过高分或尝试次数来显示排名。
let rankChoice = ["highScore","attempt"]
@State var listRank : [Player] = []
@State var selectedIndex = 0 // gives selected index from Picker
Player的定义如下:
Struct Player: Identifiable {
var id = UUID
let pla
目前,我有以下代码:
import UIKit
struct ToBeSearched {
var value1 = "1"
var value2 = "3"
var value3 = "3"
var boolean = true
}
var data = [ToBeSearched]()
var completeData = [ToBeSearched]()
public func updateSearchResults(for searchController: UISearchController) {
class Person{
var name: String
init(_ name: String){
self.name = name
}
}
struct Stuff{
var name: String
var owner: Person1
}
let jenna = Person("jenna")
var mac = Stuff(name: "Macbook pro", owner: jenna)
let ownerKeyPath = \Stuff.owner.name
mac[keyPa
是否可以使用键值编码访问对象的超类属性?
我试过这样的方法:
class Bar: Foo {
var shouldOverridePropertyOfFoo: Bool = false
var propertyOfFoo: String {
if shouldOverrideProperty {
return "property of Bar"
} else {
return value(forKeyPath: "super.propertyOfFoo") as!
在Swift 4.0中,我有一个结构数组。是否有一种方法可以使用keyPaths来更新数组中的所有项而不使用像map或forEach这样的手动迭代?类似于objc [people makeObjectsPerformSelector: @selector(setName:) withObject: @"updated"];的东西
struct Person {
var name: String? = "Empty"
}
var people = [Person(), Person()]
//This only updates one person:
p