js跳转页面带多个参数传递

// 假设你要跳转到 'destination.html' 并传递参数 name 和 age
let name = "John Doe";
let age = 30;

// 对参数进行URL编码
let encodedName = encodeURIComponent(name);
let encodedAge = encodeURIComponent(age);

// 构建完整的URL
let url = `destination.html?name=${encodedName}&age=${encodedAge}`;

// 跳转到新页面
window.location.href = url;

// 获取URL中的查询字符串部分
let queryString = window.location.search;
let urlParams = new URLSearchParams(queryString);

// 解析参数
let name = urlParams.get('name');
let age = urlParams.get('age');

console.log(`Name: ${name}, Age: ${age}`);

<form id="myForm" action="destination.html" method="post">
  <input type="hidden" name="name" value="John Doe">
  <input type="hidden" name="age" value="30">
</form>

<script>
  // 提交表单
  document.getElementById('myForm').submit();
</script>