js 菜单图片点击切换代码

以下是一个使用 JavaScript 实现菜单图片点击切换的简单示例代码：

<!DOCTYPE html>
<html lang="en">

<head>
  <meta charset="UTF-8">
  <meta http-equiv="X-UA-Compatible" content="IE=edge">
  <meta name="viewport" content="width=device-width, initial-scale=1.0">
  <title>图片切换菜单</title>
  <style>
    .menu {
      display: flex;
      justify-content: center;
      margin-top: 50px;
    }

    .menu img {
      width: 100px;
      height: 100px;
      margin: 0 10px;
      cursor: pointer;
    }
  </style>
</head>

<body>
  <div class="menu">
    <img src="image1.jpg" alt="图片 1" id="menuImage">
    <img src="image2.jpg" alt="图片 2">
    <img src="image3.jpg" alt="图片 3">
  </div>

  <script>
    const menuImage = document.getElementById('menuImage');
    let currentImageIndex = 1;

    menuImage.addEventListener('click', () => {
      currentImageIndex++;
      if (currentImageIndex > 3) {
        currentImageIndex = 1;
      }
      menuImage.src = `image${currentImageIndex}.jpg`;
    });
  </script>
</body>

</html>

基础概念：