我有关于Executequery的问题:错误消息:“指定的类型转换无效”。我试着这样做:但同样的错误也是如此。k.column2 = {2} and p.IDForeignColumn1 = k.IDcolumn and p.IDForeignColumn2 = a.IDcolumn"
var qq = db.ExecuteQuery
createStatement = conn.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE, ResultSet.CONCUR_UPDATABLE);executeQuery.afterLast();
while (executeQuery.previous) { //15th l
我要做一个问题和答案的数据库。我用sqlitedatabase浏览器做了一个数据库,放在了Assets文件夹中。这是我的代码,用于检索特定问题id所在的行。有列: id,问题,答案当我在question.java中编写查询时,显示未声明的错误id。这是我的DatabaseHelper类代码
//The And
php$ExecuteQuery->Statement = "INSERT INTO transactionsissuance', $time FROM users WHERE acct_number NOT LIKE '1800%' AND type <> 1 AND user_active = 1)";
$ExecuteQuery"", "
connection.prepareStatement(query); ResultSet result = preparedStmt.executeQueryat line 1ResultSet result = preparedStmt.executeQuery(query);
我正在尝试将查询应用于XAMPP MySQL数据库。