代码如下:select name ,concat_ws(', ', collect_list(courses)) as coursesfrom studentgroup by..."History","Art"]Alice["Math","Science"]Emma["Math","English","Science"]David["Science"]select name, collect_list...ArtDavid['Science']ScienceEmma['Math', 'English', 'Science']Math, English,Science踩坑2select name ,array(collect_list...,查询选修数据的同学的所有选修课程,结果中的选修课程是数组类型-- 创建表的第二种形式,student_copy 是create table student_copy as select name, collect_list...Science","Math, Science"]Emma["Math","English","Science","Math, English,Science"]David["Science"]需求8:如何排序呢