我一直在努力解决这个问题,但我做得不够。
这是我的代码:
'attempts and completions loop
'attempts
do
do
Wscript.StdOut.WriteLine "How many attempts did " & QB & " throw: "
attempts = Wscript.StdIn.ReadLine
if IsNumeric(attempts) then
我有如下表中的数据,并试图使用替换来完成它,但在使用替换后,我将以双分号‘;或分号结尾结束。我可以使用拆分和替换来实现这个或任何其他方法吗?
Test attempts;My attempts using operation;Additions, deletions, and modifications
Test attempts;My attempts using operation
Test attempts;access to information;attempts using nex;Additions, deletions, and modificatio
我有以下简单的数字猜测程序
import System.Random
turn :: Int -> Int -> Int -> IO ()
turn number attempt attempts =
do
if attempts == 0
then putStrLn "You lose"
else if attempt==number
then putStrLn "You got it!"
else if attempt==0
我尝试在更新行的同时打印多行,例如:
Attempts1: 10
Attempts2: 10
我试过了:
from time import sleep
import subprocess
while True:
for number in range(100):
print("Attempts1: {}".format(number))
print("Attempts2: {}".format(number))
sleep(0.1)
subprocess.call("clear")
但是文本一直在闪烁,这不是
using System;
using System.Collections;
using System.Collections.Generic;
using UnityEngine;
using UnityEngine.UI;
public class AttemptCounter : MonoBehaviour {
public Text AttemptText;
public int Attempts = 1;
public int AddAttempts = 1;
public void AddAttempt()
{
Att
我试图在python中做一个随机数游戏,在那里计算机必须生成一个介于1到20之间的数字,你必须猜出来。我已经将猜测的数量限制在6。如果用户猜错了,如何打印用户的猜测?这是我的代码:
import random
attempts = 0
name = input("What is your name? ")
random = random.randint(1, 20)
print(name + ",","I'm thinking of a number between 1 and 20, What is it?")
while att
过去几天我一直在做这件事。有什么改进的想法吗?(笔记非常简单,这是为学校准备的,而笔记必须是为Python的新手准备的)。
import random # Allows the computer to generate random numbers, vital for the program to function correctly.
import sys # Allows a new selection of system related commands to be used; I use sys.exit() to close the p
我对Python和编程很陌生,我正在尝试制作“猜测数字”的游戏。我让它工作,但我希望添加选项关闭游戏使用制动器语句。我已经试了两天了,但我想我还是坚持住了。
下面是工作的代码(没有关闭游戏的选项):
import random
attempts = 0
secretNumber = random.randint(1,100)
while True:
print("Guess a number between 1 and 100")
guess=input()
guess = int(guess)
attempts = attempts + 1
if(localStorage.getItem("attempts")==1) {
//Show Red color
alert('1')
}
if(localStorage.getItem("attempts")==2) {
//Show Black color
alert('2')
}
if(localStorage.getItem("attempts")==3) {
//Show white color
alert('3')
}
var attempts = Number(localSt
我有这样的代码:
procedure EstablishCommunication;
var
State : TStates;
Attempts : Byte;
procedure IncAttempts;
begin
Inc(Attempts);
end;
begin
State := stReadDeviceID;
Attempts := 0;
while True do
begin
if Attempts >= MAX_ATTEMPT
我的模特:
public class VerifyModel
{
public string PIN { get; set; }
public int Attempts { get; set; }
}
我的看法是:
@Html.HiddenFor(m => m.PIN)
@Html.HiddenFor(m => m.Attempts)
在进入视图时,我检查Model.PIN和Model.Attempts,它们包含从控制器传递的正确值,其中Attempts为非零。然而,呈现的Html是:
<input id
我正在尝试运行相同的场景大约1000次。我想测试的是,如果我登录和注销n次,应用程序是否稳定。我想出了一个办法,但看起来并不整洁。我想生成一个同样的HTML中的1000个执行的报告。
这就是我所做的
黄瓜步骤:
When I login "1000" number of times
在我的步骤中的定义是:
successful_attempts = 0
unsuccessful_attempts = 0
attempt_login = attempt_login.to_i
attempt_login.times do
我需要跟踪用户在一个简单的猜测游戏中输入的猜测次数。 我尝试过使用attempts= 0,然后将尝试次数设置为=尝试次数+ 1。即使我这样做了,即使用户猜了不止一次尝试,代码也会打印出"You have guessed in 1 attempts“。 代码: attempts = 0;
print("Hello, welcome to the game. You will be choosing a number
between 1 and 100. You can only guess up to 10 times.")
for tries in range(t
我是个初学者,这是我自己从零开始编写的第二个程序,我用PYgame编写了一个基本的蛇游戏,但我不是自己做的,所以,你们对此有何看法?我要诚实的意见,不要涂糖!有什么问题吗?有什么改进可以做吗?
import random
print "Guess my number!"
print " What's your name?"
user_name = raw_input()
print "Hello %s, i'm thinking of a number between 1 and 20." %(user_name)
def gam
有时我的adb会断线。为什么我会变成这样:-
[2011-09-27 17:39:43 - adb]
[2011-09-27 17:39:43 - adb]This application has requested the Runtime to terminate it in an unusual way.
[2011-09-27 17:39:43 - adb]Please contact the application's support team for more information.
[2011-09-27 17:39:49 - DeviceMonitor]
刚进入python,所以我决定做一个绞刑者游戏。运行良好,但我想知道是否有任何我可以做的优化或清理代码的方法。另外,如果有人能推荐一个我下一步可以做的项目,那就太酷了。
import sys
import codecs
import random
def printInterface(lst, attempts):
""" Prints user interface which includes:
- hangman drawing
- word updater """
for
我是个C新手,我需要从文本文件中获取特定的信息。文本文件格式为:
2015-01-01 12:00:01 rossi S
2015-01-02 12:00:01 bianchi F
2015-01-02 12:00:20 bianchi F
2015-01-03 00:00:01 rossi S
2015-01-03 11:12:20 verdi F
这是struct声明
struct login_attempt{
int day, month, year, hour, minute, second;
char username[10];
cha
代码: a = "1"
b = "2"
c = "3"
d = "4"
e = "5"
f = "6"
g = "7"
h = "8"
i = "9"
attempts = 2
while attempts > 0:
board = f'| {a} | {b} | {c} |\n| {d} | {e} | {f} |\n| {g} | {h} | {i} |'
a = "x"
attemp
这个Python代码能用一种更Python的方式编写吗?
'''
This scripts ask a user for the capital city of Peru, South America
'''
question = 'What is the capital city of Peru?'
answer = 'Lima'
# Ask question
print question
# Game continues as long as question is not answered
# Game
我是编程新手,所以请原谅下面的乱七八糟的东西……我正在试着写一个猜数字的游戏。计算机应该随机生成一个介于1和10之间的数字。用户只允许3次尝试正确猜测数字。当用户猜测正确或尝试次数不足时,我应该让程序询问用户是否想再玩一次,游戏应该重新开始。下面是我想出来的。我认为我把这件事变得比be...what复杂得多,我做错了是因为它不工作吗?
import random
number = random.randint(1,10)
print "The computer will generate a random number between 1 and 10. Try to gues
class loginattempts{
public $max_attempts = 5;
public function loginAttempts(){
global $ALIST;
$user_ip = $_SERVER["REMOTE_ADDR"];
$user_locked = "locked";
if($user_max_attempts >= $this->max_attempts){
// update ip statue to locked //
我试图帮助我的朋友做一个猜测项目,但由于某种原因,猜测变量是NoneType。你能帮助我和我的朋友吗? 注意:出于技术原因,我已经将input()替换为"hi“。 answer = "whatthing" #Change this to the answer
still_guessing = True
attempts = 1
guess = 'hi'
while still_guessing and attempts < 3:
print(f'{guess}')
if guess == answer.lower():
嗨,我还在尝试调试这个问题,所以我已经按照PHP手册把事情简化到了最基本的部分。 SP: DROP IF EXISTS(`login_validator`);
CREATE PROCEDURE `login_validator` (
IN Username VARCHAR(75),
OUT ReturnValue VARCHAR(1000)
)
BEGIN
END PHP调用: $SP1SQL = 'call login_validator(:Username, :ReturnValue)';
$Stmt = $DBConnection->Prepare