Xamarin.Forms on按钮单击打开带有项目列表的弹出窗口

using Xamarin.Forms;

public class MainPage : ContentPage
{
    public MainPage()
    {
        Button openPopupButton = new Button
        {
            Text = "打开弹出窗口"
        };

        openPopupButton.Clicked += OnOpenPopupButtonClicked;

        Content = new StackLayout
        {
            Children = { openPopupButton }
        };
    }

    private async void OnOpenPopupButtonClicked(object sender, EventArgs e)
    {
        // 创建项目列表
        ListView projectListView = new ListView
        {
            ItemsSource = GetProjectList(),
            ItemTemplate = new DataTemplate(() =>
            {
                Label nameLabel = new Label();
                nameLabel.SetBinding(Label.TextProperty, "Name");
                return new ViewCell { View = nameLabel };
            })
        };

        // 创建弹出窗口
        await Application.Current.MainPage.DisplayAlert("项目列表", null, "关闭", "确定", new ContentPage
        {
            Content = projectListView
        });
    }

    private List<Project> GetProjectList()
    {
        // 获取项目列表数据
        // 这里可以从数据库或其他数据源获取项目列表数据
        // 返回一个包含项目信息的List<Project>对象
    }
}

public class Project
{
    public string Name { get; set; }
    // 其他项目属性
}