Xamarin android:单击推送通知打开应用程序时，异步等待呼叫不起作用

public async void HandleNotificationClick()
{
    // 异步等待呼叫
    await SomeAsyncMethod();
    // 在异步操作完成后执行的代码
    // 打开应用程序的相关逻辑
}

public async Task SomeAsyncMethod()
{
    await Task.Run(() =>
    {
        // 异步操作的代码
    });
}

// 创建通知
NotificationCompat.Builder builder = new NotificationCompat.Builder(this)
    .SetContentTitle("标题")
    .SetContentText("内容")
    .SetSmallIcon(Resource.Drawable.icon);

// 设置点击事件处理程序
Intent intent = new Intent(this, typeof(MainActivity));
PendingIntent pendingIntent = PendingIntent.GetActivity(this, 0, intent, PendingIntentFlags.OneShot);
builder.SetContentIntent(pendingIntent);

// 发送通知
NotificationManager notificationManager = (NotificationManager)GetSystemService(Context.NotificationService);
notificationManager.Notify(0, builder.Build());