WHEN timestampdiff(day,curdate(),data.duedate) between 8 and 14 then 2 WHEN timestampdiff(month,curdate(),data.duedate) between 3 and 6 then 6 WHEN timestampdiff(year,curdate(),da
浏览 4提问于2017-02-15得票数 1
回答已采纳
1回答
SELECT IF(TIMESTAMPDIFF(YEAR, '2017-10-13 16:57:27', NOW()) > 0, TIMESTAMPDIFF(YEAR, '2011-01-19 16:57:27', NOW()), ' yıl ',
MOD(TIMESTAMPDIFF(MONTH, '2011-01-19 16:57:27', NOW()), 12
浏览 35提问于2020-06-18得票数 0
回答已采纳
and Newborn'when (TIMESTAMPDIFF(Month,res_Bday,CURDATE())<=13 and TIMESTAMPDIFF(Month,res_Bday,CURDATE())<=24) then 'T
浏览 0提问于2018-04-20得票数 2
回答已采纳
1回答
为什么在运行TIMESTAMPDIFF()时，在中运行TIMESTAMPDIFF()时得到一个？我的问题是：SELECT test_name, TIMESTAMPDIFF(MINUTE,'start_time','end_time') AS Duration
FROM exam_answers
浏览 0提问于2017-12-30得票数 2
回答已采纳
我有两列日期时间，我想将它们的区别显示为'yyyy-mm-dd hh:MM:ss'。我的假设是，间隔永远不会变成负值。SELECT CONCAT(DATEDIFF(`to`, `from`), " ", TIMEDIFF(`to`, `from`))0 00:00:000000-00-00 00:00:00
浏览 1提问于2014-06-28得票数 0
回答已采纳
显然，TIMESTAMPDIFF in MySQL在DateTime表达式方面做得很好，比如 (SELECT TIMESTAMP(start_time)start_time AND
TIME(NOW()) <= end_time) AS start_time
浏览 2提问于2018-10-30得票数 1
回答已采纳
, NOW()) > 11) AS survival_12m, (SELECT sum(CASE WHEN (TIMESTAMPDIFF(MONTH, START_DATE, END_DATE) > 35) then 1 else 0 END)/count(START_DATE) where TIMESTAMPDIFF(MONTH, START_DATE, NOW
浏览 2提问于2021-01-22得票数 0
回答已采纳
我的参考选择： WHEN TIMESTAMPDIFF(YEAR, STR_TO_DATE(DataNascimento, '%d/%m/%Y'),CURDATE()) < 4 THEN 'Menos de 4'
WHEN TIMESTAMPDIFF(YEAR, STR_TO_DATE(DataNascimento, '%d/%m/%Y'),CURDATE()) BETWEEN 5 AND 9 T
浏览 23提问于2017-07-28得票数 0
4回答
SELECT TIMESTAMPDIFF( YEAR, str_to_date( CONCAT( 19, bdate ) , '%Y %m %d' ) , entry),WHEN TIMESTAMPDIFF(YEAR, str_to_date(CONCAT(19, bdate), '%Y %m %d'), entry) <= 35 THEN 2
WHEN TIMESTAMPDIFF(YEAR, str_to_date(CONCAT(19, bdate), '%Y %m %d
浏览 7提问于2014-02-28得票数 1
回答已采纳
SELECT TIMESTAMPDIFF(DAY,NOW(),FECHA_FIN) AS DAY, TIMESTAMPDIFF(MINUTE,NOW(),FECHA_FIN)-TIMESTAMPDIFF(HOUR,NOW
浏览 2提问于2013-05-11得票数 2
1回答
SELECT'IF(TIMESTAMPDIFF(MINUTE, now(), end_at) > 1440, timestamp / 7, timestamp ) as minutesLeft'
FROM
浏览 0提问于2015-10-01得票数 0
回答已采纳
我有以下工作查询，它以小时为单位计算员工的应计时间，但我需要将11和14更改为(14 & 18)，如果为manager=1CASE THEN '0'hiredate, NOW()) <= 60WHEN <
浏览 33提问于2018-07-24得票数 1
回答已采纳
我在使用出生日期显示年龄阶段时遇到了问题，下面是我的查询和示例图像res_fName,res_mName,rg.gender_Name,(SELECT IF (TIMESTAMPDIFF(YEAR,res_Bday,CURDATE()) <=1,'INFANT','')
浏览 0提问于2018-03-03得票数 1
回答已采纳
1回答
我试着把两次时间戳相加在几分钟内：WHERE TIMESTAMPDIFF(MINUTE,first_date,second_date),) > 15 AND status='Pending'SELECT COUNT(*) from `table` AddTime(<e
浏览 6提问于2015-05-07得票数 2
回答已采纳
我试着把它理解为：但是我得到了下一个错误：ERROR: function timestampdiff(unknown, timestamp without time zone, timestamp without time zone) doesnot exist
LINE 1: SELECT * FROM "E
浏览 766提问于2018-10-22得票数 0
2回答
我使用这个查询: SELECT NOW() - date AS elapsed FROM ...或者，有没有更好的方法来获取运行时间并像这样用PHP生成："2分钟前“"3小时前”“昨天22:32”
浏览 0提问于2011-09-14得票数 5
下面的TIMESTAMPDIFF函数每月只计算30天。当月份小于或大于30天时如何使用TIMESTAMPDIFF函数？2012年1月1日)SUPPLIER_CODE, OTHER_VOUCHER_DATE,SUM(CASE
浏览 0提问于2015-03-11得票数 0
4回答
我有以下代码：FROM tier TIMESTAMPDIFF( HOUR, now(), FROM_UNIXTIME(expireAt) ) < 72AND TIMESTAMPDIFF( HOUR, now(), FROM_UNIXTIME(expireAt) ) > 0
您可以看到，有两次TIMESTAMPDIFF计算。
浏览 1提问于2021-03-21得票数 2
select username, when TIMESTAMPDIFF(HOUR, lastlogin, '2016-05-03 16:39:01')<1then concat(TIMESTAMPDIFF(MINUTE, '2016-05-03 16:39:01', lastlogin), ' mins')
when TIMESTAMPDIFF(DAY, lastlogin, '2016-05-03 16:39
浏览 2提问于2016-05-04得票数 1
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