Swift:如何为数组中的变量赋值？

var numbers = [1, 2, 3, 4, 5]
numbers[2] = 10 // 将索引为2的元素改为10
print(numbers) // 输出: [1, 2, 10, 4, 5]

let numbers = [1, 2, 3, 4, 5]
let doubledNumbers = numbers.map { $0 * 2 }
print(doubledNumbers) // 输出: [2, 4, 6, 8, 10]

var numbers = [1, 2, 3, 4, 5]
numbers.forEach { number in
    print(number * 2)
}
// 输出:
// 2
// 4
// 6
// 8
// 10

let numbers = [1, 2, 3, 4, 5]
let evenDoubledNumbers = numbers.filter { $0 % 2 == 0 }.map { $0 * 2 }
print(evenDoubledNumbers) // 输出: [4, 8]

let numbers = [1, 2, 3, 4, 5]
let sum = numbers.reduce(0, +)
print(sum) // 输出: 15

if numbers.indices.contains(2) {
    numbers[2] = 10
}

var strings = ["1", "2", "3"]
// 下面的代码会导致编译错误，因为 "10" 是 String 类型，而 strings 数组期望的是 Int 类型
// strings[0] = "10"

// 正确的做法是将字符串转换为整数
if let number = Int("10") {
    strings[0] = String(number)
}