Spring JPA -如何根据多列返回不同的结果

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;

@Entity
public class User {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private String name;
    private Integer age;

    // Getters and Setters
}

import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.data.jpa.repository.Query;
import org.springframework.stereotype.Repository;

import java.util.List;

@Repository
public interface UserRepository extends JpaRepository<User, Long> {

    // 根据name和age查询
    @Query("SELECT u FROM User u WHERE u.name = ?1 AND u.age = ?2")
    List<User> findByNameAndAge(String name, Integer age);

    // 根据多个字段查询并返回不同的结果
    @Query("SELECT new com.example.UserDTO(u.id, u.name, u.age) FROM User u WHERE u.name = ?1")
    List<UserDTO> findByNameWithDifferentResult(String name);
}

package com.example;

public class UserDTO {
    private Long id;
    private String name;
    private Integer age;

    public UserDTO(Long id, String name, Integer age) {
        this.id = id;
        this.name = name;
        this.age = age;
    }

    // Getters and Setters
}