Python从导入csv列表中获取url的标题状态代码并打印

import csv
import requests
from bs4 import BeautifulSoup

with open('urls.csv', 'r') as file:
    reader = csv.DictReader(file)
    for row in reader:
        url = row['url']

response = requests.get(url)
status_code = response.status_code

soup = BeautifulSoup(response.text, 'html.parser')
title = soup.find('title').text

print(f"URL: {url}")
print(f"Title: {title}")
print(f"Status Code: {status_code}")

import csv
import requests
from bs4 import BeautifulSoup

with open('urls.csv', 'r') as file:
    reader = csv.DictReader(file)
    for row in reader:
        url = row['url']
        response = requests.get(url)
        status_code = response.status_code
        soup = BeautifulSoup(response.text, 'html.parser')
        title = soup.find('title').text

        print(f"URL: {url}")
        print(f"Title: {title}")
        print(f"Status Code: {status_code}")