Python:在比较两个列表的字符串相似度时，仅保留最大外部循环结果

def calculate_similarity(str1, str2):
    m = len(str1)
    n = len(str2)
    
    # 创建一个二维数组用于保存计算结果
    dp = [[0] * (n + 1) for _ in range(m + 1)]
    
    # 初始化第一行和第一列
    for i in range(m + 1):
        dp[i][0] = i
    for j in range(n + 1):
        dp[0][j] = j
    
    # 动态规划计算编辑距离
    for i in range(1, m + 1):
        for j in range(1, n + 1):
            if str1[i - 1] == str2[j - 1]:
                dp[i][j] = dp[i - 1][j - 1]
            else:
                dp[i][j] = min(dp[i - 1][j], dp[i][j - 1], dp[i - 1][j - 1]) + 1
    
    # 计算相似度
    similarity = (1 - dp[m][n] / max(m, n)) * 100
    
    return similarity

# 示例调用
list1 = ['apple', 'banana', 'orange']
list2 = ['aple', 'bananna', 'ornge']
similarity = calculate_similarity(' '.join(list1), ' '.join(list2))
print(f"The similarity between list1 and list2 is {similarity:.2f}%.")