post = $this->_diContainer->wordy_app_doctrine->fetch(
"SELECT p,c FROM Wordy\Entity\Post p LEFTJOIN p.children c WHERE p.site = :site AND p.id = :id AND p.language = :language AND p.status !id AS id15, p1_.title AS title20, p1_.status AS status23,
Select C.comment, C.commenter, C.datecommented, B.postid, B.dateshared A.username A.avatar from B LeftJoin C Leftjoin A on C.postid = B.postid AND A.userid = C.commenter where B.postid IN ('1','2','3'syntax; check the man
我无法在leftjoin中获取所有记录。.*, states.name as state FROM cities LEFTJOIN states ON cities.states_id = states.id,它工作得很好 ->leftjoin('states', 'cities.states_id', '=', 'states.id')
因此,我需要通过查看一个字段从MySQL表中选择数据,并查看其中是否包含某个单词,然后在动态生成的where子句中执行大量其他操作。在过去使用旧的mysql扩展时,我会这样做:`field` rlike "(?=.] leftjoin [bunch of stuff] where
match(`field`) against(
MAX(grand.grand_level) AS level,pam.original_title,um.name LEFTJOIN package_master AS pam ON pam.id = grand.package_id
LEFTJOIN user_master AS um ON um.id = grand.user_idWHERE grand.package_id='d47kndffqc
JOIN questions ON users.id = questions.user_id LEFTJOIN answers ON users.id = answers.user_id LEFTJOIN follow as follow1 ON users.id = follow1.from_user LEFTJOIN follow as follow2 ON users.id = follow2但是当使用相同的查询时,我将WHERE IN的<e