Kotlin -如何使地图可序列化

import java.io.Serializable

data class Location(val latitude: Double, val longitude: Double)

data class Map(val name: String, val locations: Map<String, Location>) : Serializable

fun main() {
    val locations = mapOf(
        "Location 1" to Location(37.7749, -122.4194),
        "Location 2" to Location(34.0522, -118.2437)
    )

    val map = Map("My Map", locations)

    // 序列化地图对象
    val serializedMap = serialize(map)

    // 反序列化地图对象
    val deserializedMap = deserialize<Map>(serializedMap)

    println(deserializedMap)
}

fun serialize(obj: Serializable): ByteArray {
    // 实现序列化逻辑，将对象转换为字节数组
    // 这里可以使用任何你喜欢的序列化库，比如Kryo、Jackson等
    // 示例中使用Java标准库的ObjectOutputStream
    val outputStream = ByteArrayOutputStream()
    val objectOutputStream = ObjectOutputStream(outputStream)
    objectOutputStream.writeObject(obj)
    objectOutputStream.close()
    return outputStream.toByteArray()
}

fun <T> deserialize(bytes: ByteArray): T {
    // 实现反序列化逻辑，将字节数组转换为对象
    // 这里可以使用任何你喜欢的序列化库，比如Kryo、Jackson等
    // 示例中使用Java标准库的ObjectInputStream
    val inputStream = ByteArrayInputStream(bytes)
    val objectInputStream = ObjectInputStream(inputStream)
    val obj = objectInputStream.readObject()
    objectInputStream.close()
    @Suppress("UNCHECKED_CAST")
    return obj as T
}