Javascript检查字符串中的三个升序字母和数字

function hasThreeConsecutiveAscending(str) {
    for (let i = 0; i < str.length - 2; i++) {
        let charCode1 = str.charCodeAt(i);
        let charCode2 = str.charCodeAt(i + 1);
        let charCode3 = str.charCodeAt(i + 2);

        // 检查是否是字母或数字
        if ((charCode1 >= 48 && charCode1 <= 57) || (charCode1 >= 65 && charCode1 <= 90) || (charCode1 >= 97 && charCode1 <= 122)) {
            // 检查是否连续升序
            if ((charCode2 === charCode1 + 1) && (charCode3 === charCode2 + 1)) {
                return true;
            }
        }
    }
    return false;
}

// 示例用法
console.log(hasThreeConsecutiveAscending("abc")); // true
console.log(hasThreeConsecutiveAscending("123")); // true
console.log(hasThreeConsecutiveAscending("a1b2c3")); // false
console.log(hasThreeConsecutiveAscending("xyz")); // true
console.log(hasThreeConsecutiveAscending("987")); // false