Jackson XML到JSON的转换:如何在转换过程中通过保留内部值来排除XML中的特定标记？

<!-- Maven -->
<dependency>
    <groupId>com.fasterxml.jackson.dataformat</groupId>
    <artifactId>jackson-dataformat-xml</artifactId>
    <version>2.12.5</version>
</dependency>
<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.12.5</version>
</dependency>

<user>
    <name>John Doe</name>
    <age>30</age>
    <email>john.doe@example.com</email>
    <password>secret</password>
</user>

public class User {
    private String name;
    private int age;
    private String email;

    // Getters and setters
}

import com.fasterxml.jackson.dataformat.xml.XmlMapper;

public class XmlToJsonConverter {
    public static void main(String[] args) throws Exception {
        // 创建XmlMapper对象
        XmlMapper xmlMapper = new XmlMapper();

        // 将XML转换为Java对象
        User user = xmlMapper.readValue(xmlString, User.class);

        // 将Java对象转换为JSON字符串
        String jsonString = xmlMapper.writeValueAsString(user);

        System.out.println(jsonString);
    }
}

public class User {
    private String name;
    private int age;
    private String email;

    @JsonIgnore
    private String password;

    // Getters and setters
}