()) > '1' and datediff(hh,a.DateRecv,GETUTCDATE()) <= '2' THEN 1 ELSE 0 END) as '2',SUM(case when datediff(hh,a.DateRecv,GETUTCDATE()) > '3' and datediff(hh,a.DateRecv,GETUTC
浏览 1提问于2015-08-24得票数 0
我试过使用CTE，但我真的想不出如何在这里使用datediff：ASFROM recency_cte谢谢。
浏览 2提问于2014-07-02得票数 0
回答已采纳
下面说明了IF() function的语法id,IF(DATEDIFF( Date_PEC, Data_Analysis ) > 45, "KO", "OK") DateDiff_2,
IF(DATEDIFF( Data_Analysis, Date_communic
浏览 3提问于2022-05-27得票数 2
回答已采纳
2回答
(day,@CheckIn,getdate()) >0 and DATEDIFF(day,@CheckOut,getdate())+100 <0 THEN 100 WHEN DATEDIFF(day,getdate(
浏览 3提问于2017-06-25得票数 0
SET @dateDiff = DATEDIFF(hour,@TimeIn,@TimeOut); -- 30 days is 720 hour
BEGIN
SET @totalPrice += (@dateDiff%720) * @monthlyPriceSET @dateDiff = @dateDiff - (@da
浏览 2提问于2018-10-21得票数 0
回答已采纳
1回答
我对DateDiff有一个问题(两个日期之间的月数) SELECTWHEN X IS NOT NULL THEN
CONVERT(varchar(4), DATEDIFF(YEAR, A, GETDATE())) + ' years '+
CAST(DATEDIFF(mm, DATEADD(yy, DATEDIFF
浏览 4提问于2017-02-24得票数 0
周期性计算AND [Choose Period]=-1ANDthen [(Actuals+Planned) NNS]AND
DATEDIFF("mont
浏览 3提问于2015-09-27得票数 1
回答已采纳
2回答
老化桶DAX配方问题
、、、
我有一张表如下所示，4522 101112 -1121135 2012254 60MEM_ID dateDiff Measure
4522 10) <= 1，"0"，IF(MAX(DateDiff)>=1 & MAX(DateDiff)<15，&q
浏览 2提问于2018-09-12得票数 1
回答已采纳
import datetime
con.execute([SQL: 'SELECT datediff(minute, %(datediff_2)s, %(datediff_3)s) AS datediff_1'][parameters: {'datediff_3': datetime.d
浏览 5提问于2017-02-27得票数 9
回答已采纳
12:00:05 AM'
SET @Date2 = '2012-28-12 12:00:00 AM'
VB.Net
DateDiff(DateInterval.Day,Convert.ToDateTime("26-12-2012 12:00:我的两点意见是，SQL Server的DateDiff只减去日期时间值(28 - 26)
浏览 6提问于2012-12-26得票数 2
回答已采纳
我尝试删除datetime以使用date，但仍然收到错误
datediff(day, -6, DATETIME('2015-06-30'))/7-datediff(day, -5,DATETIME('2015-05-2
浏览 1提问于2015-06-16得票数 0
,DATEADD(MONTH, DATEDIFF(MONTH, -1, @D)-1, -1))-DATEPART(ISO_WEEK,DATEADD(MONTH, DATEDIFF(MONTH, 0, @, DATEDIFF(WEEK, 0,DATEADD(DAY, 0 - DATEPART(DAY, DATEADD(MONTH, DATEDIFF(MONTH, 0, @D)-1, 0)), DATEADD, DATEDIFF(MONTH, 0, @D)-1, 0))
ELS
浏览 25提问于2022-11-22得票数 1
(year, BOR.dob, getdate()) >= 10 AND datediff(year, BOR.dob, getdate()) < 20 THEN '10-20'WHEN datediff(year, dob, getdate()) >= 30 A
浏览 10提问于2020-10-20得票数 0
回答已采纳
1回答
$crdatefile = date("Y-m-d H:i:s",filemtime($_filename)); $datediff= $crdatefile - $date1; if ($datediff < 0) {$datediff = $d
浏览 6提问于2022-09-23得票数 0
回答已采纳
1回答
我使用DATEADD(ww, DATEDIFF(ww, 0, GETDATE()), 0)来开始一周运行几个报告，但是当它在周日运行时，它使用的是下一周而不是当前一周。SELECT DATEDIFF(WEEK, '20160527', GETDATE()) Wks, DATEDIFF(Day, '20160527', GETDATE()) Dys
SELECT DATEDIFF(WEEK, '20160528', GETDATE()) Wks, DATED
浏览 5提问于2016-06-03得票数 3
回答已采纳
3回答
(YYYY,birth_date,getdate()) <= 30 THEN 'Under 30' WHEN datediff(YYYY,birth_date,getdate()) BETWEEN 40 AND 49 THEN '40-49'WHEN datediff(YYYY,birth_date,getdate())
浏览 7提问于2014-06-11得票数 2
回答已采纳
2回答
作品(bankcleared - checkdate) as DateDiff where (bankcleared is not null) 向Where添加DateDiff -不起作用select payeeid, EXTRACT(WEEKDAY FROM checkdate) as DOW,
(bankcleared
浏览 1提问于2011-02-18得票数 3
回答已采纳
(WEEKDAY,created, closed)*10*60) WHEN CLOSED IS NULL THEN DATEDIFF(WEEKDAY,created, closed)*10*60 - DATEDIFF(MINUTE,CAST('08IN ('Saturday','Sunday') AND CLO
浏览 2提问于2012-02-07得票数 1
回答已采纳
1回答
这是我的基本“测试” , DATEADD(dd, DATEDIFF(dd, 0, getdate()), 0)
,case when DATEADD(ms,-2,DATEADD(dd, DATEDIFF(dd, 0, getdate()), 0)) != DATEADD(dd, DATEDIFF(dd, 0, getdate()), 0) then 'N
浏览 0提问于2015-08-12得票数 7
回答已采纳
1回答
'1' if datepart(month, @outdate) = 1 if round((datediffset @earnedpremium = @premium * (@january /100)
else if round((datediffearnedpremium = @premium * ((@january + @february + @march) / 100
浏览 0提问于2011-01-08得票数 0
回答已采纳
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