Dart如何将泛型函数传递给isolate

import 'dart:isolate';

void main() async {
  final receivePort = ReceivePort();
  final isolate = await Isolate.spawnFunction(runGenericFunction, receivePort.sendPort);
  final sendPort = await receivePort.first;

  final result = await sendReceive(sendPort, 'Hello');
  print(result); // 输出：Hello World

  isolate.kill();
}

void runGenericFunction(SendPort sendPort) {
  final receivePort = ReceivePort();
  sendPort.send(receivePort.sendPort);

  receivePort.listen((message) {
    if (message is String) {
      final result = genericFunction<String>(message);
      sendPort.send(result);
    }
  });
}

T genericFunction<T>(T value) {
  return value;
}

Future<dynamic> sendReceive(SendPort sendPort, dynamic message) {
  final receivePort = ReceivePort();
  sendPort.send([message, receivePort.sendPort]);
  return receivePort.first;
}