Ajax如何将表单数据与ID一起发送到控制器

<form id="myForm">
  <input type="text" id="name" name="name" placeholder="姓名">
  <input type="text" id="id" name="id" placeholder="ID">
  <button type="button" onclick="sendFormData()">提交</button>
</form>

<script>
function sendFormData() {
  var name = document.getElementById("name").value;
  var id = document.getElementById("id").value;

  var xhr = new XMLHttpRequest();
  var url = "your_controller_url"; // 替换为实际的控制器URL

  xhr.open("POST", url, true);
  xhr.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
  xhr.onreadystatechange = function() {
    if (xhr.readyState === XMLHttpRequest.DONE && xhr.status === 200) {
      var response = xhr.responseText;
      // 在此处可以处理控制器返回的数据
    }
  };
  xhr.send("name=" + name + "&id=" + id);
}
</script>

<?php
$name = $_POST['name'];
$id = $_POST['id'];

// 在此处进行相应的处理
// ...

// 返回数据给前端
$response = "处理结果";
echo $response;
?>