1000个列表中所有元素的快速平均值:返回1个值

def calculate_average(numbers):
    if not numbers:
        return 0
    total = sum(numbers)
    average = total / len(numbers)
    return average

# 示例列表
numbers = [1, 2, 3, ..., 1000]  # 假设这是一个包含1000个元素的列表

# 计算平均值
average_value = calculate_average(numbers)
print("平均值:", average_value)

def calculate_average(numbers):
    if not numbers:
        return 0  # 或者返回None或其他合适的默认值
    total = sum(numbers)
    average = total / len(numbers)
    return average

def calculate_average(numbers):
    numbers = [num for num in numbers if isinstance(num, (int, float))]
    if not numbers:
        return 0
    total = sum(numbers)
    average = total / len(numbers)
    return average