从给定的pandas数据帧中,找到四舍五入为2位小数的请求的总体接受率,可以通过以下步骤来解决:
import pandas as pd
data = {'Request': [1, 2, 3, 4, 5],
'Acceptance': [0.876, 0.934, 0.789, 0.912, 0.956]}
df = pd.DataFrame(data)
df['Acceptance'] = df['Acceptance'].round(2)
total_acceptance = df['Acceptance'].mean()
完整的代码如下:
import pandas as pd
data = {'Request': [1, 2, 3, 4, 5],
'Acceptance': [0.876, 0.934, 0.789, 0.912, 0.956]}
df = pd.DataFrame(data)
df['Acceptance'] = df['Acceptance'].round(2)
total_acceptance = df['Acceptance'].mean()
总体接受率是四舍五入为2位小数的请求的平均接受率。
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