通过引用从两个列表中移除对象

// 使用filter()方法移除对象
let list1 = [{id: 1, name: 'A'}, {id: 2, name: 'B'}, {id: 3, name: 'C'}];
let list2 = [{id: 2, name: 'B'}, {id: 4, name: 'D'}, {id: 5, name: 'E'}];

list1 = list1.filter(obj => obj.id !== 2);
list2 = list2.filter(obj => obj.id !== 2);

console.log(list1); // 输出: [{id: 1, name: 'A'}, {id: 3, name: 'C'}]
console.log(list2); // 输出: [{id: 4, name: 'D'}, {id: 5, name: 'E'}]

# 使用列表推导式移除对象
list1 = [{'id': 1, 'name': 'A'}, {'id': 2, 'name': 'B'}, {'id': 3, 'name': 'C'}]
list2 = [{'id': 2, 'name': 'B'}, {'id': 4, 'name': 'D'}, {'id': 5, 'name': 'E'}]

list1 = [obj for obj in list1 if obj['id'] != 2]
list2 = [obj for obj in list2 if obj['id'] != 2]

print(list1)  # 输出: [{'id': 1, 'name': 'A'}, {'id': 3, 'name': 'C'}]
print(list2)  # 输出: [{'id': 4, 'name': 'D'}, {'id': 5, 'name': 'E'}]