迭代2个列表并在相应位置返回值

function iterateLists(list1, list2) {
  var result = [];
  var length = Math.min(list1.length, list2.length);
  
  for (var i = 0; i < length; i++) {
    result.push([list1[i], list2[i]]);
  }
  
  return result;
}

var list1 = [1, 2, 3];
var list2 = ['a', 'b', 'c'];
var result = iterateLists(list1, list2);
console.log(result); // 输出 [[1, 'a'], [2, 'b'], [3, 'c']]

def iterate_lists(list1, list2):
    result = []
    length = min(len(list1), len(list2))
    
    for i in range(length):
        result.append((list1[i], list2[i]))
    
    return result

list1 = [1, 2, 3]
list2 = ['a', 'b', 'c']
result = iterate_lists(list1, list2)
print(result)  # 输出 [(1, 'a'), (2, 'b'), (3, 'c')]