计算字符串中多个元素的更好方法

import re

def calculate_sum(text):
    pattern = r'\d+'  # 匹配连续的数字
    numbers = re.findall(pattern, text)  # 提取匹配的数字
    numbers = [int(n) for n in numbers]  # 将字符串数字转换为整数
    return sum(numbers)

text = '1,2,3,4,5'
result = calculate_sum(text)
print(result)  # 输出：15

def calculate_sum(text):
    numbers = text.split(',')  # 将字符串按逗号分割成多个子串
    numbers = [int(n) for n in numbers]  # 将字符串数字转换为整数
    return sum(numbers)

text = '1,2,3,4,5'
result = calculate_sum(text)
print(result)  # 输出：15