获取除最新时间之外的每个月的最小日期的所有记录

import datetime

# 假设记录的日期数据存储在一个名为records的列表中
records = [
    {'id': 1, 'date': datetime.datetime(2022, 1, 5)},
    {'id': 2, 'date': datetime.datetime(2022, 1, 10)},
    {'id': 3, 'date': datetime.datetime(2022, 2, 3)},
    {'id': 4, 'date': datetime.datetime(2022, 2, 15)},
    {'id': 5, 'date': datetime.datetime(2022, 3, 8)},
    {'id': 6, 'date': datetime.datetime(2022, 3, 20)},
    {'id': 7, 'date': datetime.datetime(2022, 4, 1)},
]

# 存储每个月的最小日期的字典
min_dates = {}

# 遍历所有记录的日期
for record in records:
    year = record['date'].year
    month = record['date'].month
    date_key = (year, month)

    # 更新每个月的最小日期
    if date_key not in min_dates or record['date'] < min_dates[date_key]:
        min_dates[date_key] = record['date']

# 获取除最新时间之外的每个月的最小日期的记录
result = []
latest_date = max(min_dates.values())

for date_key, min_date in min_dates.items():
    if min_date != latest_date:
        result.append(min_date)

# 打印结果
for record in result:
    print(record)