获取列表中的最小值和最大值[closed]

numbers = [3, 1, 4, 1, 5, 9, 2, 6, 5, 3, 5]
min_value = min(numbers)
max_value = max(numbers)
print(f"最小值: {min_value}, 最大值: {max_value}")

const numbers = [3, 1, 4, 1, 5, 9, 2, 6, 5, 3, 5];
const minValue = Math.min(...numbers);
const maxValue = Math.max(...numbers);
console.log(`最小值: ${minValue}, 最大值: ${maxValue}`);

import java.util.Arrays;

public class Main {
    public static void main(String[] args) {
        int[] numbers = {3, 1, 4, 1, 5, 9, 2, 6, 5, 3, 5};
        int minValue = Arrays.stream(numbers).min().getAsInt();
        int maxValue = Arrays.stream(numbers).max().getAsInt();
        System.out.println("最小值: " + minValue + ", 最大值: " + maxValue);
    }
}

numbers = []
if numbers:
    min_value = min(numbers)
    max_value = max(numbers)
else:
    min_value = None
    max_value = None
print(f"最小值: {min_value}, 最大值: {max_value}")

mixed_list = [3, "1", 4, "5"]
# 确保所有元素都是整数
int_list = [int(x) for x in mixed_list]
min_value = min(int_list)
max_value = max(int_list)
print(f"最小值: {min_value}, 最大值: {max_value}")