给定错误的二进制文件中的最大连续数

def find_max_consecutive_ones(binary_file):
    max_count = 0
    current_count = 0

    with open(binary_file, 'rb') as file:
        byte = file.read(1)
        while byte:
            byte_value = ord(byte)  # 将字节转换为整数

            # 对每个比特位进行处理
            for i in range(8):
                bit = (byte_value >> i) & 1  # 获取比特位的值
                if bit == 1:
                    current_count += 1
                else:
                    max_count = max(max_count, current_count)
                    current_count = 0

            byte = file.read(1)

    max_count = max(max_count, current_count)  # 考虑最后一个连续数

    return max_count