有没有更好的方法来获取字典列表中的字典值？

# 示例字典列表
dict_list = [
    {'name': 'Alice', 'age': 25},
    {'name': 'Bob', 'age': 30},
    {'name': 'Charlie', 'age': 35}
]

# 获取每个字典中的'name'值
names = [d['name'] for d in dict_list]
print(names)  # 输出: ['Alice', 'Bob', 'Charlie']

# 获取每个字典中的'age'值
ages = list(map(lambda d: d['age'], dict_list))
print(ages)  # 输出: [25, 30, 35]

import pandas as pd

# 将字典列表转换为DataFrame
df = pd.DataFrame(dict_list)

# 获取'name'列的值
names = df['name'].tolist()
print(names)  # 输出: ['Alice', 'Bob', 'Charlie']

import numpy as np

# 假设dict_list中的每个字典都有一个'age'键
ages = np.array([d['age'] for d in dict_list])
print(ages)  # 输出: [25 30 35]

# 示例字典列表
dict_list = [
    {'name': 'Alice', 'age': 25},
    {'name': 'Bob'}
]

# 尝试获取不存在的键'gender'
try:
    genders = [d['gender'] for d in dict_list]
except KeyError as e:
    print(f"KeyError: {e}")

genders = [d.get('gender', 'Unknown') for d in dict_list]
print(genders)  # 输出: ['Unknown', 'Unknown']

# 示例字典列表
dict_list = [
    {'name': 'Alice', 'age': 25},
    {'name': 'Bob', 'age': '30'}  # age是字符串类型
]

# 尝试获取'age'值并进行数值计算
try:
    ages = [int(d['age']) for d in dict_list]
except ValueError as e:
    print(f"ValueError: {e}")

ages = []
for d in dict_list:
    try:
        ages.append(int(d['age']))
    except (KeyError, ValueError):
        ages.append(None)
print(ages)  # 输出: [25, None]